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Hello,


I want to override this menu item :

<menuitem name="AAA"
id="purchase.menu_purchase_rfq"
parent="purchase.menu_procurement_management"/>

So this is the good id and parent because I can move it as I want, but name = "AAA" as no effect.

I tried to update the action too but it doesn't work :

<record id="purchase.purchase_rfq" model="ir.actions.act_window">
<field name="name">AAAA</field>
</record>

Could you help me please.

Thx

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Huỷ bỏ

<record id="purchase.menu_purchase_rfq" model="ir.ui.menu">

<field name="name">AAAA</field>

</record>

Tác giả

Yeah I tried with model="ir.ui.menu" and everything as you wrote. Sorry for mistake before.

But still not working.

String is still the same

Tác giả

Up please, someone have an idea

Tác giả

Up n2 is it a bug of Odoo ?

Câu trả lời hay nhất

Do like this

<record id="purchase.menu_purchase_rfq" model="ir.ui.menu">
    <field name="name">AAAA</field>
</record>
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Tác giả Câu trả lời hay nhất

I've tried Muhammad but got this error :


    " you can't define a `%s` record with this ID." % (xml_id, real_model, model)

ParseError: "External ID conflict, menu_purchase_rfq already refers to a `ir.ui.menu` record, you can't defin                e a `ir.actions.act_window` record with this ID." while parsing /odoo/custom/addons/app_catalogue_achat/views                /views_company.xml:165, near

<record id="purchase.menu_purchase_rfq" model="ir.actions.act_window">

            <field name="

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