Bỏ qua để đến Nội dung
Menu
Câu hỏi này đã bị gắn cờ
1 Trả lời
2853 Lượt xem

Hi, I am able to define a kit as a selection of several products configuring variants and attibutes (ex select 1 cold apetizer among 3 options, 1 warm apetizer among 5 options an 1 dessert among 4 options), BUT i am unable to allow choosing multiple elemments in the kit (ex select 2 cold apertizer, 4 warm apetizer and 1 dessert). Of course i can´t trick the system with attributes "cold apetizer 1, cold apetizer 2..." and get the same end with multiple single choices. But I would like to know if it is possible to do it without \tricking.... That is, multiples choices of apetizer. Thanks

Ảnh đại diện
Huỷ bỏ

You want to select more than 1 cold appetizer. can you not set the quantity to 2 units of the same cold appetizer?

Tác giả

Sorry this was an answer to NomadKing. I have no solved the problem "Yes, i can set more than 1 of the "same" appetizer. But what i am looking for is to be able to choose two different appetizers.  Let´s say the atribute is "cold appetizer" and there is 5 values for it: Salmon blini, tuna blini, beef blini, pork blini & chicken. When configuring the product I want to be able to select 2 values of the attribute "cold appetizer". Thanks"

Câu trả lời hay nhất

I believe you should create all possible combinations as values of the cold appetizer attribute.
For example: 
Attribute: Cold Appetizer 

Values:  Salmon blini; tuna blini; beef blini; pork blini; chicken; salmon & tuna blini ; salmon & beef blini ; salmon & pork blini; salmon & chicken blini; tuna & beef blini ; tuna & pork blini ; tuna & chicken blini ; beef & pork blini ; beef & chicken blini ; pork & chicken blini. 
Those are single and double combo. But you can extend it to make 3, 4, 5 combos as well. Same for warm appetizers and desserts.

Its a tedious task but it's only way I can think of.

Cheers!

Ảnh đại diện
Huỷ bỏ
Tác giả

Thanks King. I am trying to avoid that kind of solutions because for a cocktail we have options to up to 6 choices among 12. So, hughe number of combinations. But perhaps it´s the only way. Thanks anyway

Bài viết liên quan Trả lời Lượt xem Hoạt động
0
thg 12 21
94
1
thg 11 22
2248
1
thg 4 22
2131
0
thg 3 22
946
0
thg 1 23
1537