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one2many10.0
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jalena@bcsytv.com

I have this model.


class A(models.Model):

    list = fields.One2many('B',)

     @api.onchange('field')

             data = {}

             a.list.new(data)


I now change a field, how should I build Class B this model, Class B is a new model

class B(models.Model):

    aaa = fields.One2many('C',)

class C(models.Model):

    ccc = fields.many2one('product.product')



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Bréndou Serge Eric

hello! I would like to help but i dont clearly understand your problem

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Francis Louie Del Rosario
Best Answer

Hi,


'categories': fields.one2many('p_c.category', 'property_id', 'Categories'),
Parameters
  • comodel_name -- name of the target model (string)
  • inverse_name -- name of the inverse Many2one field in comodel_name (string)
  • domain -- an optional domain to set on candidate values on the client side (domain or string)
  • context -- an optional context to use on the client side when handling that field (dictionary)
  • auto_join -- whether JOINs are generated upon search through that field (boolean, by default False)
  • limit -- optional limit to use upon read (integer)
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Mayank Gosai
Best Answer 
Hope this may be helpful:

(0, 0,  { values })    link to a new record that needs to be created with the given values dictionary
(1, ID, { values })    update the linked record with id = ID (write *values* on it)
(2, ID)                remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID)                cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID)                link to existing record with id = ID (adds a relationship)
(5)                    unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs])          replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)

Regards,
Mayank Gosai
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