Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:

CRM
e-Commerce
Účtovníctvo
Sklady
PoS
Projektové riadenie
MRP

All apps

All Posts People Badges

Tagy (View all)

odoo accounting v14 pos v15

About this forum

Pomoc

How remove user from multiple groups at once Odoo 12

user groups odoo odoo12

2 Replies

7593 Zobrazenia

Pawan Kumar Sharma

Hello All,

I want to remove the user from multiple groups at once when changing from an 'individual' to 'company' on write method of a contact form.

@api.multi
def write(self, values):
    user = self.env['res.users'].search([('partner_id', '=', self.id)])
    if 'company_type' in values:
        if values["company_type"] == "company":
            # want to add in below group
            """[(6, 0, [self.env.ref('base.group_user').id,
                                           self.env.ref('sales_team.group_sale_salesman_all_leads').id,
                                           self.env.ref('survey.group_survey_manager').id
                                           ])]"""

            # want to remove from below group
            """[(6, 0, [self.env.ref('base.group_portal').id,
                                           self.env.ref('survey.group_survey_user').id,
                                           ])]"""
    res = super(Contact, self).write(values)
    return res

Thanks in advance

Malay Khamar (Serpent Consulting Services Pvt. Ltd.)

Best Answer

Hello,

You can try this,

@api.multi
def write(self, values):
    user = self.env['res.users'].search([('partner_id', '=', self.id)])
    if 'company_type' in values:
        if values["company_type"] == "company":
            # want to add in below group
            user.write({'groups_id': [(4, self.env.ref('base.group_user').id),
                                                    (4, self.env.ref('sales_team.group_sale_salesman_all_leads').id),
                                                    (4, self.env.ref('survey.group_survey_manager').id)
                                                       ]})
            # want to remove from below group
           user.write({'groups_id': [(3, self.env.ref('base.group_portal').id),
                                                    (3, self.env.ref('survey.group_survey_user').id),
                                                        ]})
    res = super(Contact, self).write(values)
    return res

You can also use like this:

    user.write({'groups_id': [(4, self.env.ref('base.group_user').id),
                                            (4, self.env.ref('sales_team.group_sale_salesman_all_leads').id),
                                            (4, self.env.ref('survey.group_survey_manager').id),
                                            (3, self.env.ref('base.group_portal').id),
                                            (3, self.env.ref('survey.group_survey_user').id),
                                           ]})

Hope this will work for you,

Thanks

Pawan Kumar Sharma

Autor

Thanks Malay, it's working fine

Avinash Nk

Hello Pawan,

To remove a user from a group, you can do it like this

 your_group = self.env.ref('module.odoo_group', False)
 your_group.write({'users': [(3, user_id)]})


For Adding,

 your_group = self.env.ref('module.odoo_group', False) 
 your_group.write({'users': [(4, user_id)]})

You can use loop and your logic to execute all at once.


Check this for more understanding, how to write to a One2many field.

(0, 0, { values })

link to a new record that needs to be created with the

given values dictionary

(1, ID, { values })

update the linked record with id = ID (write values on it)

(2, ID)

remove and delete the linked record with id = ID

(calls unlink on ID, that will delete the object completely,

and the link to it as well)

(3, ID)

cut the link to the linked record with id = ID

(delete the relationship between the two objects but does

not delete the target object itself)

(4, ID)

link to existing record with id = ID (adds a relationship)

(5)

unlink all (like using (3,ID) for all linked records)

(6, 0, [IDs])

replace the list of linked IDs (like using (5) then (4,ID)

for each ID in the list of IDs)




Thanks & Regards
Avinash N K

Pawan Kumar Sharma

Autor

Thanks avinash, it's working

Avinash Nk

My pleasure

Enjoying the discussion? Don't just read, join in!

Create an account today to enjoy exclusive features and engage with our awesome community!

Registrácia

Related Posts	Replies	Zobrazenia
psycopg2.ProgrammingError: no existe la relación «_unknown» Please HELP!!!! odoo odoo12	2 nov 25	351
Odoo Users Creation user odoo	1 nov 23	2199
How to track One2many field in Odoo12? Solved odoo odoo12	3 nov 23	18514
Error: Couldn't load module web Solved odoo odoo12	3 nov 24	26626
How I get the current ID of a record ? Solved odoo odoo12	1 apr 23	6992

This question has been flagged

Enjoying the discussion? Don't just read, join in!