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I like to add some fields in the warehouse so I added the class with columns in the stock.py. But it shows error. I can not find what the error is.

The error message is

Traceback (most recent call last):
  File "/home/rck/Desktop/odoo-8.0/openerp/http.py", line 539, in _handle_exception    return super(JsonRequest, self)._handle_exception(exception)  File "/home/rck/Desktop/odoo-8.0/openerp/http.py", line 590, in dispatch    return self._json_response(result)  File "/home/rck/Desktop/odoo-8.0/openerp/http.py", line 528, in _json_response    body = simplejson.dumps(response)  File "/usr/local/lib/python2.7/dist-packages/simplejson/__init__.py", line 366, in dumps    return _default_encoder.encode(obj)  File "/usr/local/lib/python2.7/dist-packages/simplejson/encoder.py", line 269, in encode    chunks = self.iterencode(o, _one_shot=True)  File "/usr/local/lib/python2.7/dist-packages/simplejson/encoder.py", line 348, in iterencode    return _iterencode(o, 0)  File "/usr/local/lib/python2.7/dist-packages/simplejson/encoder.py", line 246, in default   

raise TypeError(repr(o) + " is not JSON serializable")

TypeError: product.step1() is not JSON serializable


My py code in stock.py is 

class product_step1(osv.osv):
    _name = "product.step1"   

_columns = {       

'name':fields.float('Name'),       

'b':fields.float('B'),       

'c':fields.float('C'),       

'd':fields.float('D'),       

'e':fields.float('E'),       

'f':fields.float('F'),       

'g':fields.float('G'),       

'h':fields.float('H'),       

'i':fields.float('I'),       

'j':fields.float('J'),           

}

my xml code in stock_view.xml is


<record model="ir.ui.view" id="step1_tree_view">       

<field name="name">step1.tree</field>       

<field name="model">product.step1</field>       

<field name="type">tree</field>       

<field name="arch" type="xml">       

<tree string="Product Details">       

<field name="name"/>       

<field name="b"/>       

<field name="c"/>       

</tree>        </field>        </record>


 <record model="ir.ui.view" id="step1_form_view">       

<field name="name">step1.form</field>       

<field name="model">product.step1</field>       

<field name="type">form</field>       

<field name="arch" type="xml">       

<form string="Product Details">       

<sheet>           

<group>               

<group>       

<field name="name"/>       

<field name="b"/>       

<field name="c"/>       

<field name="d"/>       

<field name="e"/>                   

</group>               

<group>                   

<field name="f"/>                   

<field name="g"/>                   

<field name="h"/>                   

<field name="i"/>                   

<field name="j"/>               

</group>           

</group>       

</sheet>       

</form>        </field>        </record>
       

<record model="ir.actions.act_window" id="action_step1_form">       

<field name="name">step1</field>       

<field name="res_model">product.step1</field>       

</record>
        <menuitem name="Product Details" parent="menu_stock_root" id="step1_menu_mainform"/>       

<menuitem name="Product Description" parent="step1_menu_mainform" id="step1_menu1_mainform" action="action_step1_form"/>  


When I click the Quants and stock Moves tab in warehouse this error has been shown.

Notify me where I'm doing the mistake.

Thank you.

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Author

And also when I click the "current inventory valuation" It shows error as

res = self._obj.execute(query, params)

DataError: division by zero

After the error the tree view and form view are not working.

I still can't find where this error comes from

Best Answer

I think that your problem is the type of 'name' field. This field is the default field used to reference this model from another one(s) as the record title. Try to declare it like 'char' or 'text'.

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