Skip to Content
This question has been flagged
1 Reply
4754 Views
Avatar
nasim

I want set a permission for a button in a form of a module. this button defined in xml file of module view with this code:

<button name="tender_validate_special_access" groups="internal_services.group_internal_services_special_access_validator" states="manager_approve" string="Validate Special Access" type="object" icon="gtk-jump-to" />

---------------------------------------------------------------------------

but I want say when form state is != darft and department_second_id.manager_id.user_id = user.id , this button for example show "readonly" or "invisible" format.

I type a attr for button in this case:

attrs="{'readonly': ['&',('state','!=','draft'),('department_second_id.manager_id.user_id','!=',user.id)]}"

--------------------------------------------------------

( department_second_idis a many2one field in this module from hr module and use in this form. user.id is current user(login user))

but does not work!

I dont know what is problem?

-------------------------------------------------------

if I type this code:

attrs="{'readonly': [('state','!=',' draft ')]}"

it is work well.


Avatar
Discard
Avatar
Qutechs, Ahmed M.Elmubarak
Best Answer

Hello,

I think I it wn't work, because in some cases you can't access filed with dot notation in the domain the simple workaround

you can make a functional [computed] "invisible" field with type boolean then then you can make the calculations if the  

'department_second_id.manager_id.user_id','!=',user.id 
it will return true otherwise false

then change your domain to:

attrs="{'readonly': ['&',('state','!=','draft'),('new_computed_fields','!=',True)]}"

Hope this could helps ...

Avatar
Discard
nasim
Author

thank for your help

I read this page for user your solution:

https://www.odoo.com/forum/help-1/question/how-to-make-a-field-invisible-using-compute-field-based-on-a-condition-98226

but in my code when I use :

@api.one

@api.depends()

--------------------------

this error display:

@api.one

NameError: name 'api' is not defined

--------------------------------------

I serach and understand that I have write "from openerp import api" in my .py file.

but again I see this error:

from openerp import api

ImportError: cannot import name api

---------------------------------------

my openerp version is 6.1

you think in this version I shoud use other code?

thanks so much

Qutechs, Ahmed M.Elmubarak

Hi, Yes you can't use api in v6.1 you can just use old API pattern in v6.1

nasim
Author

Thanks.

but how? :(

-------------------------------------

now my code is this:

_columns = {

'check_button': fields.boolean(compute='_get_value'),

---------------------------------------

def _get_value(self):

if self.department_second_id.manager_id.user_id == user.id:

self.check_button = True

else:

self.check_button = False

------------------------------------------------------------------------------

but the field "check_button" is alwayse :False

It seems that any time 'if self.department_second_id.manager_id.user_id == user.id:' does not work or not called.

I don not know what is problem!

so sorry! ... :(