I am working in accounting module, where I need to open list of  records with  specific parter_id and  record state in open. here gose my code.

ORM :

class account_payment_ext(models.Model):
    _inherit = 'account.payment'
    payment_record = fields.Char(string='Payment Records')


class account_invoice_ext(models.Model):
    _inherit = 'account.invoice'

Views 
<odoo>
  <data>

    <record id="action_account_invoice_payment_inherit" model="ir.actions.act_window">
            <field name="name">Payment</field>
            <field name="type">ir.actions.act_window</field>
            <field name="res_model">account.invoice</field>
            <field name="view_type">form</field>
            <field name="view_mode">tree,form,calendar,graph</field>
            <field name="search_view_id" ref="account.invoice_tree"/>
            <field name="domain">[('state', '=', 'open'),('partner_id', '=',partner_id)]</field>
            <field name="context">{
                'search_default_filter_partner_id': partner_id
                }
                               </field>

    </record>

     <record id="account_payment_inheirt" model="ir.ui.view">
        <field name="name">account.payment.inherit</field>
        <field name="model">account.payment</field>
        <field name="inherit_id" ref="account.view_account_payment_form"/>
        <field name="arch" type="xml">
          <data>

            <field name="amount" position="after">
              <a name="%(action_account_invoice_payment_inherit)d" type="action">Customer Invoices</a>
            </field>


          </data>
        </field>
     </record>

  </data>
</odoo>

Error says that if cannot find partner_id. I need customer invoices of sarina as in screenshot below, when Customer Invoices link is clicked. Is there any way to do this.