Create new record with Many2one relation

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Create new record with Many2one relation

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Zakaria

Hello my friends,

I would like to create a new records of class "B" from function. This record have relation Many2one with another class "A".

The class "A" have One2many relation with the class "B". My creation function is as follows :

self.env['affichage2.sensor_stock'].create({
    'sensor_type': sensorconfig,
    'serial_capture': self.internal_Serial,
    'pack_id': self.public_id,

})

The 'pack_id' of the class "B" is declared as follows :

pack_id = fields.Many2one('affichage2.pack_stock', string='Pack de capture')

The 'public_id' of class "A" is declared as follows :

public_serial = fields.Char(string="Public_Serial", required=True)

The class "A" is named by the "public_serial" field as follows : _rec_name = 'public_serial'

Axel Mendoza

Best Answer

Hi Zakaria

I think you have a mistake in the fields you shows because you left out the public_id definition, but assuming that it's:

sensor_ids = fields.One2many('affichage2.sensor_stock', 'pack_id', string='*********')

You have 2 ways to create records for the model affichage2.sensor_stock:

1- Directly create it doing it like you shows in your code by set the Many2one field pack_id

self.env['affichage2.sensor_stock'].create({
    'sensor_type': sensorconfig,
    'serial_capture': self.internal_Serial,
    'pack_id': self.public_id.id,
})

2- By making a write for the public_id field in the write format for One2many relationships:

self.public_id.write({
    'sensor_ids': [
        (0,0, {'sensor_type': sensorconfig, 'serial_capture': self.internal_Serial}),
        (0,0, {'sensor_type': 'value2', 'serial_capture': 'capture2'})
    ]
})

I add another line for value2 to show you how to create multiple records using this form, and those will be associated to self.public_id without the need to specify the pack_id value

The first way is more simple and direct than the second one but it's up to you...