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statusbarodoo8
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Siobhan

Hello

I have code for a statusbar and it is working but not as I expect:

.py code:

state = fields.Selection({('new','New'), ('open','In Progress'), ('closed','Closed')}, "Status")

.xml code:

<field name="state" widget="statusbar" statusbar_visible="new,open,closed" clickable="True"/>


problem 1:

Even though I have specified in the XML code to show new, open and closed, it shows in the order open, new, closed in Odoo. How do I fix this?

problem 2:

It is on the top left corner of the screen, how do I get it to the top right where most status bars are?

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Siobhan
Author

Found another issue I can't find information on. How do I get the created tickets to default to new when saved?

Siobhan
Author

Ankit Thank you.. Problem 1 sorted. status bar is now on the left side. Problem 2: how do I get them in order new, inprogress, closed and Problem 3: how can I get it to default to new when create is clicked

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Ankit Gauri
Best Answer

hello siobhan

in .py file

'state': fields.selection([('open', 'Open'), ('post', 'Posted')], "Batch State"),

_defaults = {

'state': 'open',

in.xml file

in tree view :

<field name="state"/>

you can try this in form view: 

<field name="state" widget="statusbar" />

or you can use this

<field name="state" widget="statusbar" statusbar_visible="draft,confirm,done"/>

Thank You

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Siobhan
Author

Tried using _defaults. I have no error but state is not defaulting to new. Tree view and form view are already in place.

Ankit Gauri

it will work if you have put that code in header

Ankit Gauri

there is no issue in your code also

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Siobhan
Author Best Answer

Ok.. got help with answer. I was using dictionary for my list which python will print in random order. Slight change in the code and added the default in same line so solves all my issues:



state = fields.Selection(

[('new','New'), ('open','In Progress'), ('closed','Closed')],

default='new',

string="Status",

)

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