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Performan action wizard from create method

By
Omar OUHARI
on 4/17/16, 12:10 PM 1,020 views

Hello cummunity,

How it'is possible to perform an action wizard from create method.

I try this :

class ResPartner(models.Model):    
    _inherit = 'res.partner'
    
    @api.model
    def create(self, vals):
        partner_ids = self.search([('name', 'like', vals['name'])])
        if partner_ids:
            return self.button_partner_list(partner_ids)
        return super(ResPartner, self).create(vals)

    @api.multi
    def button_partner_list(self, partner_ids):
        return {
            'type': 'ir.actions.act_window',
            'res_model': 'wizard.res.partner',
            'view_type': 'form',
            'view_mode': 'form',
            'target': 'new',
            'context': {
                'default_partner_ids': [(6, 0, partner_ids.ids)]
            }
        }

class WizardResPartner(models.TransientModel):
    _name = 'wizard.res.partner'
    partner_ids = fields.Many2many('res.partner', string='Partners')
I got this error when I run this code:

Odoo Server Error
Traceback (most recent call last):
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 643, in _handle_exception
    return super(JsonRequest, self)._handle_exception(exception)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 680, in dispatch
    result = self._call_function(**self.params)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 316, in _call_function
    return checked_call(self.db, *args, **kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\service\model.py", line 118, in wrapper
    return f(dbname, *args, **kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 309, in checked_call
    result = self.endpoint(*a, **kw)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 959, in __call__
    return self.method(*args, **kw)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\http.py", line 509, in response_wrap
    response = f(*args, **kw)
  File "C:\Users\iPod\PycharmProjects\crf\server\addons\web\controllers\main.py", line 892, in call_kw
    return self._call_kw(model, method, args, kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\addons\web\controllers\main.py", line 884, in _call_kw
    return getattr(request.registry.get(model), method)(request.cr, request.uid, *args, **kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\api.py", line 250, in wrapper
    return old_api(self, *args, **kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\api.py", line 355, in old_api
    return downgrade(recs, result, *args, **kwargs)
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\api.py", line 273, in <lambda>
    return lambda self, *args, **kwargs: downgrade(args[0])
  File "C:\Users\iPod\PycharmProjects\crf\server\openerp\models.py", line 4106, in <lambda>
    @api.returns('self', lambda value: value.id)
AttributeError: 'dict' object has no attribute 'id'

I know that create method expects res_partner object in return but how can I return an action dict ?
Any Idea !!

0
Axel Mendoza
On 4/18/16, 12:33 AM

You cannot do that in the create. Just put a button for that

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Asked: 4/17/16, 12:10 PM
Seen: 1020 times
Last updated: 4/18/16, 12:33 AM