[JavaScript] Can't call _super() in an asynchronous call

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[JavaScript] Can't call _super() in an asynchronous call

5 Replies

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javascript view extend include super

Thanh Loyal

Hello,

I modify a view like bellow:

local.ScKanbanGroup = instance.web_kanban.KanbanGroup.include({
    init: function (parent, records, group, dataset) {          
        var self = this;        
        var res_user = new openerp.web.Model('res.users');         
        res_user.call('get_picking_type_ids', null)
                .then(function (response) {
                    // generate new records array base on response
                    self._super(parent, newRecords, group, dataset);                
                 });    
     }, ...

I need to pass 'newRecords' to the parent init function but what I get is TypeError: self._super is not a function.

Please help.

Thank you!

Shawn Varghese

Best Answer

Your _super() call is inside the asynchronous part of the method.

You need to assign it to a different variable and then call that. Could you try this:

local.ScKanbanGroup = instance.web_kanban.KanbanGroup.include({
 init: function (parent, records, group, dataset) {
    var self = this;     
    var _super=this._super.bind(this);
    var res_user = new openerp.web.Model('res.users');   
    res_user.call('get_picking_type_ids', null)          
    .then(function (response) {
     // generate new records array base on response    
     _super(parent, newRecords, group, dataset);