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I'm trying to validate a field

By
Uillino
on 8/17/15, 6:25 AM 723 views

I'm tryng to validate a field, so I've written this code:

        @api.one
@api.constrains('code')
def control_code(self):
i=0
a=1
while i<9:
if i==0:
if unicode.isdigit(self.code[0]):
a=i+1
raise Warning(("Warning!\nThe character %s must be a letter") % (a))
elif i in range (1,4) or i in range (5,10):
if not unicode.isdigit(self.code[i]):
raise Warning(('Warning!\nThe character %s must be a number') % (a))
elif i == 4:
if self.code[i] is not '/':
raise Warning(("Warning!\nThe character %s must be '/'") % (a))
i=i+1
a=a+1

Everything works fine, except for i==4. Even if I put a '/', I get the warning message.

Anyone knows why?

2
Drees Far
On 8/17/15, 6:46 AM

Hi friend:

Try this

if self.code[i] !=  '/':

raise Warning(("Warning!\nThe character %s must be '/'") % (a))

Use != (preferred) or <> (deprecated). See comparison operators : https://docs.python.org/release/2.5.2/lib/comparisons.html. For comparing object identities, you can use the keyword is and its negation is not.

Regards.


It works! Thank you!

Uillino
on 8/17/15, 7:18 AM

Happy for you :) You Re WELCOME

Drees Far
on 8/17/15, 7:20 AM
1
Axel Mendoza
On 8/17/15, 6:47 AM

Maybe because you are checking if self.code[i] is not '/' and raising the error based in var a, when:

i = 4

a = 5

Maybe you expect some string in code like:

'http://www'

For something like this you need to check:

if self.code[a] is not '/':


0

Try

if self.code[i] != chr(47):



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Asked: 8/17/15, 6:25 AM
Seen: 723 times
Last updated: 8/17/15, 7:18 AM