Skip to Content
Menu
This question has been flagged

I was creating a quotation from code and have the id of that quotation how to get the id of the assorted subscription the oder has the subscription counter at (1)


the counter has this action in odoo

def _compute_subscription_count(self):
        """Compute the number of distinct subscriptions linked to the order."""
        for order in self:
            sub_count = len(self.env['sale.order.line'].read_group([('order_id', '=', order.id), ('subscription_id', '!=', False)],
                                                    ['subscription_id'], ['subscription_id']))
            order.subscription_count = sub_count


def action_open_subscriptions(self):
        """Display the linked subscription and adapt the view to the number of records to display."""
        self.ensure_one()
        subscriptions = self.order_line.mapped('subscription_id')
        action = self.env.ref('sale_subscription.sale_subscription_action').read()[0]
        if len(subscriptions) > 1:
            action['domain'] = [('id', 'in', subscriptions.ids)]
        elif len(subscriptions) == 1:
            form_view = [(self.env.ref('sale_subscription.sale_subscription_view_form').id, 'form')]
            if 'views' in action:
                action['views'] = form_view + [(state,view) for state,view in action['views'] if view != 'form']
            else:
                action['views'] = form_view
            action['res_id'] = subscriptions.ids[0]
        else:
            action = {'type': 'ir.actions.act_window_close'}
        action['context'] = dict(self._context, create=False)
        return action

I think sub_count without len is the answer but I don't understand it


can you please help



Avatar
Discard
Related Posts Replies Views Activity
1
Jun 20
2634
1
Aug 21
1233
1
Apr 21
2416
0
Apr 21
1379
1
May 20
2388