Raise an error in Odoo 8

Question

Hello, I am developing a module in Odoo 8. I have inherited product.pricelist class which definition is

class product_pricelist(osv.osv):

In my definition I have

class product_pricelist(models.Model):
_inherit = 'product.pricelist'

When in my code I try to execute the line

raise osv.except_osv(_('Warning!'), _("At least one pricelist has no active version !
Please create or activate one."))

I have an error because global name osv is not defined. What is the best way to throw an exception

Zbik · Accepted Answer

You use openerp.exceptions ( except_orm() or Warning() ) like this:

from openerp.exceptions import except_orm, Warning, RedirectWarning
class product_pricelist(models.Model):
_inherit = 'product.pricelist'

@api.multi
def FOO(self):
if True:
raise except_orm('FOO','Lorem ipsum dolor sit amet')
else:
raise Warning('Lorem ipsum dolor sit amet')

Umesh Choudhari · Answer

@zbik , I tried what u said but it gives error as follows
Traceback (most recent call last):
File "/opt/odoopro/openerp/http.py", line 539, in _handle_exception
return super(JsonRequest, self)._handle_exception(exception)
File "/opt/odoopro/openerp/http.py", line 1417, in _dispatch_nodb
func, arguments = self.nodb_routing_map.bind_to_environ(request.httprequest.environ).match()
File "/usr/lib/python2.7/dist-packages/werkzeug/routing.py", line 1433, in match
raise NotFound()
NotFound: 404: Not Fo

José · Answer

Thanks, it works! But how can I display a warning message and then continue with the execution of the method?

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