If you want to serve multiple domains with multiple databases, whereas each domain is connected to one particular database, it is best to run Odoo using the dbfilter option, see https://www.odoo.com/documentation/10.0/setup/deploy.html. If you want to serve multiple websites from one database, it is not officially supported and does not work flawlessly. Check the web for Odoo and Website multi or similar and you'll find plenty of content regarding this topic.

Yes you can do that in 2 database (if default odoo instalation without buy module multiple website)

1 odoo server

2 database

2 domain

You can setting with dbfilter

Hi ,

you have to decide , like what the above advices given , 

1. to host it with each domain has it's own database on the same IP (recommended)

or

2. to host it with all domains on the same IP ( not commonly practice ) in ONE db, with this method,

i saw a few modules out there , some needs to pay , like this one , https://www.odoo.com/apps/modules/10.0/pr1_multi_website/ , not sure if this is what you are looking for ?

Thanks.

kalmen

Always and always i suggest use other webserver like apache / nginx and as Imran said configure those.

You should use apache / nginx and configuration of your /etc/hosts file to direct traffic from www.abc.com to the correct instance of Odoo and same www.xyz.com

I am assuming the themes are at least for two separate DBs, i don't think its possible within the same Odoo DB.  We have done similar multiple DBs on same host server, but you can also run multiple Odoo Servers with different ports on same server

you can alter the domain part in ir_http to return correct urls. 

i have x-forward-proto for detecting http/https for proper url generation. 

def _get_root_url(trim=False):
    """
    add X-Forwarded-Proto
    :param trim:
    :return:
    """

    url_root = request.httprequest.url_root

    if trim is True:
        url_root = request.httprequest.url_root[:-1]

    for k, v in request.httprequest.headers.items():
        if k.lower() == 'x-forwarded-proto' and v.lower() == 'https':
            url_root = re.sub(r'^http://', 'https://', url_root)
            break

    return url_root