Hi, i want to check if developer mode is active inside a function, so if is active i will send a more descriptive error message inside a function that can raise and exception, and if is not active i will only show a simple error to user.
Cette question a été signalée
1
Répondre
7501
Vues
Two options that come to mind are using has_group('base.group_no_one') on the logged in user, or checking if the URL contains debug=.
Good Luck,
Jake Robinson
Hello
Reinhart
Here you can get your solution.
Write bellow code in your method you can easily get active mode status.
from openerp.http import request
and check weather debug mode active or not.
print "====Checking Debug mode active or not=====", request.debug
Vous appréciez la discussion ? Ne vous contentez pas de lire, rejoignez-nous !
Créez un compte dès aujourd'hui pour profiter de fonctionnalités exclusives et échanger avec notre formidable communauté !
S'inscrire| Publications associées | Réponses | Vues | Activité | |
|---|---|---|---|---|
|
0
nov. 16
|
7626 | ||
|
0
déc. 23
|
3770 | ||
|
2
janv. 21
|
8617 | ||
|
Report in custom module
Résolu
|
|
2
mars 20
|
7038 | |
|
1
oct. 18
|
7568 |
Hello
Reinhart
Here you can get your solution.
Write bellow code in your method you can easily get active mode status.
from openerp.http import request
and check weather debug mode active or not.
print "====Checking Debug mode active or not=====", request.debug