So i have 3 categorys. first is without childs, second is always has a child but some times dosnt have parent and some times doescategorys = parent_id + parent_parent + categ_id
and third category is always without a parent.
And my goal is to go over this 3 categorys starting from bottom to top.
first i need to check category without child, second the secodn category and then third.
if my condition is met i just desplay the message, if conditions not meet i go to another category and check for condition.
so i wrote this code and it's kinda ok, but maybe i could do it without repeating myself , and make my code more simple?
for line in order.order_line:
parent_id = line.product_id.categ_id.parent_id
parent_parent = line.product_id.categ_id.parent_id
categ_id = line.product_id.categ_id
categorys = parent_id + parent_parent + categ_id
for categ in categorys:
if not categ.childs_id and categ.qty_for_discount:
if line.product_qty < categ.qty_for_discount:
msgs.append(
msg % (
categ.qty_for_discount - line.product_qty,
line.product_id.uom_id.name,
categ.name
)
)
elif categ.parent_id and categ.child_id and categ.qty_for_discount:
if line.product_qty < categ.qty_for_discount:
msgs.append(
msg % (
categ.qty_for_discount - line.product_qty,
line.product_id.uom_id.name,
categ.name
)
)
else:
if line.product_qty < categ.qty_for_discount:
msgs.append(
msg % (
categ.qty_for_discount - line.product_qty,
line.product_id.uom_id.name,
categ.name
)
)
Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:
- 客戶關係
- e-Commerce
- 會計
- 庫存
- PoS
- Project
- MRP
此問題已被標幟
3799
瀏覽次數
相關帖文 | 回覆 | 瀏覽次數 | 活動 | |
---|---|---|---|---|
|
9
3月 20
|
42146 | ||
|
2
10月 18
|
4034 | ||
|
1
10月 17
|
4289 | ||
|
1
3月 15
|
4914 | ||
|
1
3月 15
|
4763 |