Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:
Dear All,
There this a Binary field in my customize model.
file = fields.Binary(string='File', required=True)
and I need upload the data(image) in this field to other URL with requests package.
The code below is workable:
URL = ......
with open('z.jpg','wb+') as f:
f.write(base64.b64decode(self.file))
f.seek(0)
r = requests.post(URL, files={'media':f})
But have to write this data(image) to disk first. Can I fix this code and upload it without writing step?
Crie uma conta hoje mesmo para aproveitar os recursos exclusivos e interagir com nossa incrível comunidade!
Inscreva-se| Publicações relacionadas | Respostas | Visualizações | Atividade | |
|---|---|---|---|---|
|
0
jan. 22
|
3498 | ||
|
1
mai. 21
|
10139 | ||
|
0
jul. 19
|
3069 | ||
|
2
jul. 17
|
11858 | ||
|
1
mar. 16
|
5188 |
1. Use the live chat to ask your questions.
2. The operator answers within a few minutes.
Do you know of the python library named StringIO ( https://docs.python.org/2/library/stringio.html )? This will allow you to mimic file creation but instead of saving it to the disk, it will be stored in memory (RAM). This might not exactly be the solution to your problem but at least allows you to circumvent writing to disk.
I tried code below:
r = requests.post(url=url, files={'media': io.BytesIO(base64.b64decode(self.file))}
But it still not work.