Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:
Dear All,
There this a Binary field in my customize model.
file = fields.Binary(string='File', required=True)
and I need upload the data(image) in this field to other URL with requests package.
The code below is workable:
URL = ......
with open('z.jpg','wb+') as f:
f.write(base64.b64decode(self.file))
f.seek(0)
r = requests.post(URL, files={'media':f})
But have to write this data(image) to disk first. Can I fix this code and upload it without writing step?
Cree una cuenta para poder utilizar funciones exclusivas e interactuar con la comunidad.
Registrarse| Publicaciones relacionadas | Respuestas | Vistas | Actividad | |
|---|---|---|---|---|
|
0
ene 22
|
3595 | ||
|
1
may 21
|
10381 | ||
|
0
jul 19
|
3164 | ||
|
2
jul 17
|
11954 | ||
|
1
mar 16
|
5288 |
1. Use the live chat to ask your questions.
2. The operator answers within a few minutes.
Do you know of the python library named StringIO ( https://docs.python.org/2/library/stringio.html )? This will allow you to mimic file creation but instead of saving it to the disk, it will be stored in memory (RAM). This might not exactly be the solution to your problem but at least allows you to circumvent writing to disk.
I tried code below:
r = requests.post(url=url, files={'media': io.BytesIO(base64.b64decode(self.file))}
But it still not work.