how to set default date to my date_start and date_end

Question

Hello Expert,

how to set the date_end field to current day +6days, for instance the value would be date_start = 09/25/2014 then date_end = 10/01/2014. Thanks

python----

from datetime import datetime
from dateutil.relativedelta import relativedelta
from osv import osv, fields
from openerp import tools

class test_product(osv.Model):
_name = "test.product"

_columns = {

'date_start': fields.date('Date End'),
'date_end': fields.date('Date End'),

}

_defaults= {
'date_start': lambda *a: time.st

Atchuthan - Technical Consultant, Sodexis Inc · Accepted Answer

Also, we can use timedelta

For the manipulation of date, we can use timedelta to add the day by 5. For more info: https://docs.python.org/2/library/datetime.html#timedelta-objects [1]

from datetime import datetime, timedelta

_defaults={
'date_start': lambda *a:datetime.now().strftime('%Y-%m-%d'),
'date_end': lambda *a:(datetime.now() + timedelta(days=(6))).strftime('%Y-%m-%d'),
}

[1] https://docs.python.org/2/library/datetime.html#timedelta-objects

Temur · Answer

Hello,

Please make sure that you've made following imports:

*from datetime import datetime
from dateutil.relativedelta import relativedelta*

-than change your code to:

_defaults= {
'date_start': lambda *a: time.strftime('%Y-%m-%d'),
'date_end': lambda *a: *(datetime.today() + relativedelta(days=6)).strftime('%Y-%m-%d')*,
}

regards,

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