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odoo accounting v14 pos v15

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[SOLVED][odoo10]ORM: write() takes exactly 2 arguments (3 given), browse(id) or search rise error.

python orm write recordset odoo10

7 답글

19827 화면

FEDERICO LEONI

In a situation where I need to write to another model:

wt = self.env['model.name']
wt.write([id],{'field': 'value'})

rise the following error:

Traceback (most recent call last):
File "/odoo/odoo-server/odoo/http.py", line 638, in _handle_exception return super(JsonRequest, self)._handle_exception(exception) File "/odoo/odoo-server/odoo/http.py", line 675, in dispatch result = self._call_function(**self.params) File "/odoo/odoo-server/odoo/http.py", line 331, in _call_function return checked_call(self.db, *args, **kwargs) File "/odoo/odoo-server/odoo/service/model.py", line 119, in wrapper return f(dbname, *args, **kwargs) File "/odoo/odoo-server/odoo/http.py", line 324, in checked_call result = self.endpoint(*a, **kw) File "/odoo/odoo-server/odoo/http.py", line 933, in __call__ return self.method(*args, **kw) File "/odoo/odoo-server/odoo/http.py", line 504, in response_wrap response = f(*args, **kw) File "/odoo/odoo-server/addons/web/controllers/main.py", line 878, in call_kw return self._call_kw(model, method, args, kwargs) File "/odoo/odoo-server/addons/web/controllers/main.py", line 870, in _call_kw return call_kw(request.env[model], method, args, kwargs) File "/odoo/odoo-server/odoo/api.py", line 679, in call_kw return call_kw_model(method, model, args, kwargs) File "/odoo/odoo-server/odoo/api.py", line 664, in call_kw_model result = method(recs, *args, **kwargs) File "/odoo/odoo-server/addons/point_of_sale/models/pos_order.py", line 512, in create_from_ui pos_order = self._process_order(order) File "/odoo/odoo-server/addons/point_of_sale/models/pos_order.py", line 111, in _process_order pos_session.write({'sequence_number': pos_order['sequence_number'] + 1}) File "/odoo/odoo-server/odoo/models.py", line 3555, in write self._write(old_vals) File "/odoo/odoo-server/odoo/models.py", line 3763, in _write self.recompute() File "/odoo/odoo-server/odoo/models.py", line 5292, in recompute vals = rec._convert_to_write({n: rec[n] for n in ns}) File "/odoo/odoo-server/odoo/models.py", line 5292, in <dictcomp> vals = rec._convert_to_write({n: rec[n] for n in ns}) File "/odoo/odoo-server/odoo/models.py", line 5191, in __getitem__ return self._fields[key].__get__(self, type(self)) File "/odoo/odoo-server/odoo/fields.py", line 869, in __get__ self.determine_value(record) File "/odoo/odoo-server/odoo/fields.py", line 955, in determine_value self.compute_value(recs) File "/odoo/odoo-server/odoo/fields.py", line 935, in compute_value self._compute_value(records) File "/odoo/odoo-server/odoo/fields.py", line 926, in _compute_value getattr(records, self.compute)() File "/odoo/odoo-server/addons/divina_v10/models/divina_pos_V10.py", line 170, in _session_costs_control wt.write([4],{'income': '1'})TypeError: write() takes exactly 2 arguments (3 given)

Even if a browse the recordset I get an error:

wt = self.env['model.name']
wt2 = wt.browse(4)
wt2.write({'field': 'value'})

Rise another error:

Traceback (most recent call last):
File "/odoo/odoo-server/odoo/http.py", line 638, in _handle_exception return super(JsonRequest, self)._handle_exception(exception) File "/odoo/odoo-server/odoo/http.py", line 675, in dispatch result = self._call_function(**self.params) File "/odoo/odoo-server/odoo/http.py", line 331, in _call_function return checked_call(self.db, *args, **kwargs) File "/odoo/odoo-server/odoo/service/model.py", line 119, in wrapper return f(dbname, *args, **kwargs) File "/odoo/odoo-server/odoo/http.py", line 324, in checked_call result = self.endpoint(*a, **kw) File "/odoo/odoo-server/odoo/http.py", line 933, in __call__ return self.method(*args, **kw) File "/odoo/odoo-server/odoo/http.py", line 504, in response_wrap response = f(*args, **kw) File "/odoo/odoo-server/addons/web/controllers/main.py", line 878, in call_kw return self._call_kw(model, method, args, kwargs) File "/odoo/odoo-server/addons/web/controllers/main.py", line 870, in _call_kw return call_kw(request.env[model], method, args, kwargs) File "/odoo/odoo-server/odoo/api.py", line 679, in call_kw return call_kw_model(method, model, args, kwargs) File "/odoo/odoo-server/odoo/api.py", line 664, in call_kw_model result = method(recs, *args, **kwargs) File "/odoo/odoo-server/addons/point_of_sale/models/pos_order.py", line 512, in create_from_ui pos_order = self._process_order(order) File "/odoo/odoo-server/addons/point_of_sale/models/pos_order.py", line 111, in _process_order pos_session.write({'sequence_number': pos_order['sequence_number'] + 1}) File "/odoo/odoo-server/odoo/models.py", line 3555, in write self._write(old_vals) File "/odoo/odoo-server/odoo/models.py", line 3763, in _write self.recompute() File "/odoo/odoo-server/odoo/models.py", line 5292, in recompute vals = rec._convert_to_write({n: rec[n] for n in ns}) File "/odoo/odoo-server/odoo/models.py", line 5292, in <dictcomp> vals = rec._convert_to_write({n: rec[n] for n in ns}) File "/odoo/odoo-server/odoo/models.py", line 5191, in __getitem__ return self._fields[key].__get__(self, type(self)) File "/odoo/odoo-server/odoo/fields.py", line 872, in __get__ value = record._cache[self] File "/odoo/odoo-server/odoo/models.py", line 5539, in __getitem__ value = self._recs.env.cache[field][self._recs.id]KeyError: 9

Then how can I specify the recordset id where I need to write?

Axel Mendoza

베스트 답변

Just solve it like this:

self.env['model.name'].browse(id).write({'field': 'value'})

FEDERICO LEONI

작성자

It works!

But since I'm a curious person would you mind to share some other infos and explain why with

wt = self.env['model.name']

wt2 = wt.browse(id)

wt2.write({'field': 'value'})

it will not works?

Axel Mendoza

It should work too, I just compress it, but your code wasn't the same as in the comments above

the idea is to call write over a recordset returned by the browse

FEDERICO LEONI

작성자

Interesting I think it rose an error because I've tried to use a field from the original recordset (self.field) but using as a var (var = self.field) before change the recordset with self.env works.

Thanks Axel!

Jay Dasani

Hello ,

I found another way also,

record_set = self.env['model.name'].browse(id)

field_name = record_set.write({'field':value, 'field': value,})

Thanks & Regards,

Jay R. Dasani

Mahmoud Abdelwahid

Try this code:

wt = self.env['model.name']wt.write({'field': 'value'})

FEDERICO LEONI

작성자

Assuming you're referring to

wt = self.env['model.name']

wt.write({'field': 'value'})

not in a single line, I've already tried, doesn't rise any error (nor infos on log) but doesn't update the recordset since no id was specified.

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