콘텐츠로 건너뛰기
메뉴
커뮤니티에 참여하려면 회원 가입을 하시기 바랍니다.
신고된 질문입니다
3 답글
5647 화면

Hello,

I'm an odoo and python beginner and I'm building a small module for odoo, i have a model with a state attribute and i want to sort my tree view using the state field but i don't want the order to be done alphabetically.

here is my state field definition

state = fields.Selection(

[

('creation', "En création"),

('blocage', "Création"),

('listage', "A lister"),

('gel', "A geler + Analyse"),

('reponse', "A répondre"),

('avis', "Attente réponse client"),

('traitement', "En cours de traitement"),

('clos', "Clos"),

]

)

And i want the list view to be sorted according to the state so that records in 'creation' state will be the first one.

Thanks for helping.

아바타
취소

did you try it?

작성자 베스트 답변

Hello, sorry for the delay.

Thanks for your answer.


We just updated our selection fields definition to use integer indexes and display string labels for users ...

state = fields.Selection(

[

('0', "En création"),

('1', "Création"),

('2', "A lister"),

('3', "A geler + Analyse"),

('4', "A répondre"),

('5', "Attente réponse client"),

('6', "En cours de traitement"),

('7', "Clos"),

]

)

It is actually working fine.

아바타
취소
베스트 답변

I suggest you to add a computed field and order by it like this:

......

    _order = "state_order asc"

......

@api.one

@api.depends('state')

def _get_state_order(self):

    state_list = [('creation', 1),('blocage', 2),('listage', 3),('gel', 4),('reponse', 5),('avis', 6),('traitement', 7),('clos', 8)]

    self.state_order = filter(lambda x: x[0] == self.state, state_list)[0][1]

...

    state_order = fields.Integer(string='State Order',  store=True, readonly=True, compute='_get_state_order')


Haven't time to check this code let you do it :)

Hope it will do the trick.

아바타
취소
관련 게시물 답글 화면 활동
1
10월 16
4005
1
9월 15
10626
0
7월 24
1158
1
10월 19
2811
2
5월 19
20975