콘텐츠로 건너뛰기
메뉴
커뮤니티에 참여하려면 회원 가입을 하시기 바랍니다.
신고된 질문입니다
1 회신
3205 화면

I'm working on a form and the result will be the name showing in the URL.
http://domain.com/folder/{title}/show/
How do I replace characters Odoo-style!?

       title = ""

       if post.get('title') == "":
            title = "Showcase"
        else:
            title = post.get('title').
****
        # REPLACE FROM BAD/INVALID CHARS
        title = title.encode('utf-8')

       title = title.replace(" ", "_").
****
I've been struggling with this headache... What am I mIssing!?

I must have proper and Internet-friendly name for this current project, because the name och the post need to be

아바타
취소
베스트 답변

Hi, try to specify dynamic http.route urls and try to slugify the name.

Many examples might be found in the website_sale controllers: https://github.com/odoo/odoo/blob/10.0/addons/website_sale/controllers/main.py

Look at the method 'def shop', and how your goal is achieved for product category (and its proper name in the url)

아바타
취소
관련 게시물 답글 화면 활동
2
10월 16
7235
0
1월 25
686
1
12월 23
8661
2
9월 23
6799
5
12월 23
27312