hello,
I want to remove Copy Right Footer from website in Odoo 15 how do this by coding
Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:
The function to disable copyright is available OotB since version 14 and not need to do be done by coding:
- Open the website editor,
- Select the page footer
- Disable copyright
Hi,
Hi heba,
You can achieve this by using the following XML code:
<template id="web.frontend_layout" inherit_id="web.frontend_layout "><xpath expr="//t[@t-if='not not_copyright']" position="replace">
<div class="container py-3">
<div class="row">
<!-- <div class="col-sm text-center text-sm-start text-muted"> -->
<!-- <span class="o_footer_copyright_name me-2">Copyright &copy; <span t-field="http://res_company.name" target="_blank">res_company.name" itemprop="name">Company name</span></span> -->
<!-- </div> -->
<div class="col-sm text-center text-sm-end">
<t t-call="web.brand_promotion"/>
</div>
</div>
</div>
</xpath>
</template>
In this code snippet, the part related to the copyright information has been commented out. You can simply remove the comment tags (<!-- and -->) surrounding the copyright section to enable it in your website layout
Hope it helps
you can override the website template. Here's how you can do it:
odoo>
template id="custom_website_footer" inherit_id="website.footer_custom" name="Custom Website Footer" priority="100">
xpath expr="//div[@class='footer']" position="replace">
!-- Add your custom content here or leave it empty to remove the footer -->
/xpath>
/template>
/odoo>
thanks for your comment , but iget error in v15
try this way:
add dependency in manifest.py
'depends': ['website'],
step 2:inherit footer
template id="hide_footer_copyright" inherit_id="website.layout" name="Footer No Copyright" active="True">
xpath expr="//div[hasclass('o_footer_copyright')]" position="replace">
#add your custom copyright content
/xpath>
/template>
<?xml version="1.0" encoding="utf-8"?><odoo> <template id="remove_footer" inherit_id="website.layout"> <xpath expr="//footer" position="replace"> <!-- Empty footer section --> </xpath> </template></odoo>
thank you , but should I write to remove copyright only not all footer
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