تخطي للذهاب إلى المحتوى
القائمة
لقد تم الإبلاغ عن هذا السؤال
2 الردود
11306 أدوات العرض

How can I call a wizard from another module/folder??

I know where are the view and the .py what can I do for call that wizard on another menu?

الصورة الرمزية
إهمال

Which one do you want to call? Please tell me the path and i'll give you an answer according your wizard.

أفضل إجابة

If you wanted to call a wizard from button you need to write a button like

<button name='%(module_name.window_action)d' type='action' string='Button'/>

and if you have wrote a method in py file then you need to return action like

def your_method(self, cr, uid, ids, context=None):
    .....
    your code
    .....
    return {
       'name': 'Wizard name'
       'type': 'ir.actions.act_window',
       'res_model': 'wizard_model',
       'view_mode': 'form',
       'view_type': 'form',
       'target': 'new',
       'context': context,
    }

In return "target: new" will popup a wizard. This will help you to call a wizard from another module.

الصورة الرمزية
إهمال
الكاتب

I did that but I have an error

raise NotImplementedError('Many2Many columns should not be used as record name (_rec_name)') NotImplementedError: Many2Many columns should not be used as record name (_rec_name)

الكاتب أفضل إجابة

I did that but I have an error

raise NotImplementedError('Many2Many columns should not be used as record name (_rec_name)') NotImplementedError: Many2Many columns should not be used as record name (_rec_name)
What's Happen?

الصورة الرمزية
إهمال

I suppose you have defined many2many field and in that you are giving columns as name field of model, change it by suffix "id" it will work. for eg. model_id.

I suppose you have defined many2many field and in that you are giving columns as name field of model, change it by suffix "id" it will work. for eg. model_id.

الكاتب

thanks it works now

المنشورات ذات الصلة الردود أدوات العرض النشاط
3
فبراير 25
57787
2
ديسمبر 16
14599
5
أغسطس 24
46584
2
أبريل 24
2527
3
يونيو 23
5740