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Hi there,

My doubt is the following:

I want to add fields to the resource.resource model, so , as I learnt, I have to inherit from resource with the parameters set as below:

_name = 'resource.resource'

_inherit = 'resource.resource'

Then add the fields I want in the _columns parameter.

Until here everything is ok, but then I have some issues I don't know how to solve:

  • Where should I write the new class? Inside resource.py? or should I write a new .py (for example: resource2.py)

  • If I should write a new .py, where should I save it? Inside the resource folder? or in a custom folder? and besides, do I need some imports?

Any other recommendations are welcomed.

Thanks in advance

Code:

class resource_resource(osv.Model):
_name = 'resource.resource'
_inherit = 'resource.resource'
_columns = {
    'name' : fields.function(_get_full_name, type='text', 'Full Name'),
    'x_name' : fields.text('Name'),
    'x_sname' : fields.text('Surname'),
}
def _get_full_name(self,cr,uid,ids,field,arg,context=None):
    aResource = self.browse(cr,uid,ids)
    return (aResource.x_name + ' ' + aResource.x_sname)

Openerp version: 7

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Can u paste your code ?

Autor

Hi, I will edit my post with the code though my question is not about the code itself but more related to where should I put it.

Najlepsza odpowiedź

Hi, You can write in the same py file by creating different class. But its always good to write in new py file which is separated from the base module. Because when performing upgrade there is a chance that your code get deleted.

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Autor

Thanks for the answer, I would like to create a new .py, Would it be ok if I locate it in a Resource-Custom folder created by myself? Shouldn't I make some imports?

You can create a custom module and add the extra fields in the py file of inherited class. Write the _view.xml file only for the field you have newly created and give the ref as <field name="inherit_id" ref="object.yourview" />

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