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i don't want to write multiple time.
_defaults = {
'extra_cleaning_hourly_rate': lambda self, cr, uid, c: self.pool.get('res.company').browse(cr, uid, uid, c).extra_cleaning_hourly_rate,
'extra_cleaning_hourly_rate_material': lambda self, cr, uid, c: self.pool.get('res.company').browse(cr, uid, uid, c).extra_cleaning_hourly_rate_material,
'extra_cleaning_hourly_rate_material': lambda self, cr, uid, c: self.pool.get('res.company').browse(cr, uid, uid, c).window_cleaning_hourly_rate,
}
Hi Vijay,
Here you go!
- override the default_get method to achieve this.
in dictionary you have to pass key as your field name for which you want to set default value, would your updated value for that field.
#v7
def default_get(self, cr, uid, ids, context=None):
# Either prepare your dictionary here to update in result dictionary
result = super(class_name, self).default_get(cr, uid, ids, context=context) # or directly update your result dictionary with new fields value to be updatr return result
#v8
@api.model
def default_get(self, vals):
#update dictionary with default fields
result = super(product_new_revision, self).default_get(vals)
#Update dictionary with default fields
return result
eg. Update dictionary value in this format -> {'field_name': 'default value'}Hope this will help.
Regards,
Anil.
Hello,
You can use the default_get method it returns a dict mapping fields names with their default values.
You can also check an example here
Hope this could help
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it's not making sense , extra_cleaning_hourly_rate_material can have to two default on the basis on "certain condition" (so apply that condition in one lambda )