Dynamic Form from Tree View

Question

I have a tree/list view and I want to customize what form is opened when clicking on a record in the list. The record's each have a related record and each one may be from a different model. I know I can find and return the corresponding views dynamically through python but I am unsure of how to link this to the xml.

I have record 1 which has the fields res_model=mrp.production and res_id=500.
I have record 2 which has the fields res_model=stock.picking and res_id=125.

Both record 1 and 2 appe

Jonah Barrett · Accepted Answer

I ended up creating a button in the list view that ran the following action.
def action_open_record(self):
"""
Return the form view for the related record.
"""
self.ensure_one()
return {
"type": "ir.actions.act_window",
"res_model": self.res_model,
"view_type": "form",
"view_mode": "form",
"res_id": self.res_id,
"target": "current",
}
This will open the form view for the related record no matter what model it is from, while it isn't as clean as opening the form directly from the list view it is

Christophe Bellanger · Answer

Hello,
it may not be the best solution but I will create a 3rd field which would correspond to the reconstituted url. Then I would put the URL field in the list as a widget:
<field name = "file_path" widget = "url" /> Hope this can be useful to you

Adil Akbar · Answer

HI, you can follow following tutorial for this:
https://youtu.be/kwkddYoFQCE [1]
Hope it helps,
Thanks

[1] https://youtu.be/kwkddYoFQCE

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