Hi

try this function

import calendar

def onchange_type(self,cr,uid,ids,type,month,year,context=None):

res = {}

cal = calendar.Calendar()

count = 0.0

if type and month and year:

if type == '5':

for week in cal.monthdayscalendar(int(year), int(month)):

for i, day in enumerate(week):

if i not in [5,6] and day > 0:

count += 1

elif type == '5.5':

for week in cal.monthdayscalendar(int(year), int(month)):

for i, day in enumerate(week):

if i not in [5,6] and day > 0:

count += 1

elif i == 5 and day > 0:

count += .5

elif type == '6':

for week in cal.monthdayscalendar(int(year), int(month)):

for i, day in enumerate(week):

if i not in [6] and day > 0:

count += 1

res = {'value':{

'no_of_days' : count

}}

return res

i hope this will help you.

Instead of using 5, 5.5 ad 6, i would add two boolean fields on the company: is_working_saturday and is_working_sunday.

Then i would iterate over the dates and test.

if date.isoweekday() < 6:

    total+=1

if date.isoweekday() == 6 and company.is_working_saturday:

    total +=1

if date.isoweekday == 7 and company.is_working_sunday:

    total +=1

This is not completely clean (i leave you the enhancement to do :D), but with a code like this you would even be able to compute number of business day for a company that work on sunday, but not on saturday