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Serge Mercado

In manufacturing order model, I added new buttons beside create (Produce button, and Mark as Done button). I wanted the "Produce" button to pop up a wizard that will ask for a res.user and after clicking Save button, it will write the res.user to each records. How can I make this possible?

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Sudhir Arya (ERP Harbor Consulting Services)

Where do you want to write the user record? To MRP record or consumed lines or finished product or somewhere else?

Note: To update any record, you can use write method.

Serge Mercado
Autor

Hello, Sudhir and Sehrish!

The button that I meant to describe are these buttons added above the tree view.

https://imgur.com/a/tWf2cst

<t t-extend="ListView.buttons">

<t t-jquery="button.o_list_button_add" t-operation="after">

<button t-if="widget.modelName == 'mrp.production'" class="btn btn-primary oe_produce_button" type="button" accesskey="f">Produce</button>

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Autor

<blockquote class="imgur-embed-pub" lang="en" data-id="a/tWf2cst" data-context="false" ><a href="//imgur.com/a/tWf2cst"></a></blockquote><script async src="//s.imgur.com/min/embed.js" charset="utf-8"></script>

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Autor

Please disregard my other comment.

Serge Mercado
Autor

The function of that wizard will link the mrp.production to a custom model I named production.batch. Before this custom model is created, it will ask for a an attachment to be uploaded. Once I clicked save, all the records of mrp.production's field called production_batch will be filled with that of the wizard.

This is how I implemented the wizard (works on server action):

https://imgur.com/sYEVY2h

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Serge Mercado
Autor Best Answer

Just an update! This can now be implemented in Odoo 14 by adding a button in the header of a tree view.

<record id="my_view_id" model="ir.ui.view">
    <field name="name">view.name</field>
    <field name="model">my.model</field>
    <field name="arch" type="xml">
        <tree>
            <header>
                <button name="%(action_for_wizard)d" string="Action" object="action"/>
            </header>
        </tree>
    ...

When a record is selected:



When no record is selected:


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Tri Nanda

This working on Odoo14 as like what I want.

Thanks,
Tri Nanda

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Paresh Wagh
Best Answer

Hi Serge: If I have understood your question correctly, you should be able to loop through the variable "self" that gets passed to each action to get what you need.

EDIT:

Actions can be linked to buttons in one of two ways depending on where the action is defined.

If the action is defined as a server action, you can use the following syntax:

<button name="SERVER_ACTION_ID" type="action" string="BUTTON LABEL"/>

NOTE: type="action" and name=id of the server action.

The server action id can be defined to be automatically picked up at installation time (instead of hard coding it) by using the syntax

%(EXTERNAL_ID_OF_SERVER_ACTION)d

For example,

<button name="%(stock.action_stock_report)d" type="action" string="Stock Report"/>

If the action is defined as a function in the underlying object, you can use the following syntax:

<button name="FUNCTION_NAME" type="object" string="BUTTON LABEL"/>
NOTE: type="object" and name=name of the function defined in the python class of the object
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Serge Mercado
Autor

I just realized my question is incomplete, but thank you for this Paresh! This is a step further for what I was aiming for.

Serge Mercado
Autor

Hello, Paresh! What I did that worked is that I created a server action using a wizard <act_window ... />

I was referring to this tutorial at first:

https://www.odoo.com/fr_FR/forum/aide-1/how-can-i-get-the-active-ids-from-tree-view-in-odoo-11-143922

but the multi="True" is not necessary anymore and won't work in Odoo 13, and the attribute src_model is now binding_model. This is the code I used:

<act_window id="multi_production_batch_wizard"

name="Create Production Batch"

binding_model="mrp.production"

res_model="production.batch.wizard"

view_mode="form"

target="new"

/>

I was able to retrieve the selected ids using:

manufacturing_orders = self.env['mrp.production'].browse(self._context.get('active_ids'))

Serge Mercado
Autor

It only solved half of the problem, I want to implement that server action into a new button using this:

https://stackoverflow.com/questions/58514381/hide-the-create-button-in-a-specific-module-only-in-odoo11

I don't know how to call a wizard by extending the ListView.buttons as shown here: https://imgur.com/a/tWf2cst

Paresh Wagh

Hi Serge: I have edited my earlier answer and added an explanation of how to link an action to a button.

Serge Mercado
Autor

Hello Paresh, how do I implement that if the button used is like in the link below? I added a custom ListView buttons

https://stackoverflow.com/questions/58514381/hide-the-create-button-in-a-specific-module-only-in-odoo11

Serge Mercado
Autor

Hello, Paresh! This is working now in Odoo 14 since they added a header for the tree view already. Thank you!