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When i click the Refresh button below function will call. This one2many field is in hr.employee model.

def button_click(self, cr, uid, ids, context=None):
          if context is None:
             context = {}         
          res = self.pool.get('ir.actions.act_window').for_xml_id(cr, uid ,'employee_profile','action_project', context=context)
         
          res['context'] = context
          emp_ids_browse = self.browse(cr, uid, ids, context=context)[0].project_line_ids
// project_line_ids -- one2many field in hr.employee table. I have an employee_id field in the employee.project table. I want to sort the records based on employee ids. Want to display in the same page.Here the issue is emp_ids_browse didnt browse any records. I want to display all records based on employee_id.  But now it is displaying all employee records in all employee profile. How can i get values in emp_ids_browse and sorting will based on employee_id?

 


          print "emp_ids_browse",emp_ids_browse
          emp_ids=[]
          for emp in emp_ids_browse:
              emp_ids.append(emp.id)
              print "emp_ids",emp_ids
              res['project_line_ids'] = [('id','in', emp_ids)]
          return res

 

I dont want to create as a new record. Just want to display the exiting records in employee.project to hr.employee, in each employee profile

الصورة الرمزية
إهمال

So, the objective is to show "the same" one2many fields in 2 tables in different sorting order? Any reason why not "fix" the sorting order in the original field? I understand that you have hr.employee and employee.projects, linked by employee_id in employee.projects. Is the Refresh button in the view that belongs to hr.employee? If so, isn't sorting by employee_id will be meaningless anyway because for each hr.employee the project_line_ids will only have 1 employee_id?