Ir al contenido
Menú
Se marcó esta pregunta
1 Responder
7313 Vistas

One of my current projects in Odoo 13.0 requires a lot of dynamically created widgets/items. In this example my goal is to create a new menuitem, whenever a certain model gets saved into the database.

Creating a hard coded menuitem in the view.xml is fairly easy in odoo but is there a way to create a new one dynamic from the code behind e.g. JS/Python?

The possibility of creating a whole new HTML-based view with Qweb is also known, but was not my first intention because it should be in the same form as my parent module.

Avatar
Descartar
Mejor respuesta

Below is my implementation of creating a dynamic menu item. Firstly I create a new action to point the menu item too and then create the new menu item. In the below example this is being made in  a create function when I create a new record in a table. Be sure to delete these actions/menuitems manually if you uninstall and reinstall the module. Hope this helps.

action_vals = {
'name': vals['menu_name'],
'xml_id': 'module_name.documents_list_action',
'res_model': 'business.management',
'type': 'ir.actions.act_window',
'target': 'current',
'view_mode': 'tree,form',
'domain': "[('le_document_type', '=', '" + vals['menu_name'] + "')]",
}
action = self.env['ir.actions.act_window'].create(action_vals)

###get the parent menu item
parent_menu = self.env['ir.ui.menu'].search([('name', '=', 'DropDownParentMenuItem')])
for menu in parent_menu:
if menu.parent_id.name == 'ModuleParentMenuItem':
parent_id = menu.id
parent_path = menu.parent_path
menu_item_vals = {
'action': 'ir.actions.act_window,%d' % (action.id,),
'active': True,
'display_name': vals['menu_name'],
'name': vals['menu_name'],
'parent_id': parent_id,
'parent_path': parent_path,
}
menu_item = self.env['ir.ui.menu'].create(menu_item_vals)


Avatar
Descartar
Publicaciones relacionadas Respuestas Vistas Actividad
1
jun 22
6090
4
may 24
12627
1
abr 24
3269
4
ene 24
23143
2
ene 24
2438