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One of my current projects in Odoo 13.0 requires a lot of dynamically created widgets/items. In this example my goal is to create a new menuitem, whenever a certain model gets saved into the database.

Creating a hard coded menuitem in the view.xml is fairly easy in odoo but is there a way to create a new one dynamic from the code behind e.g. JS/Python?

The possibility of creating a whole new HTML-based view with Qweb is also known, but was not my first intention because it should be in the same form as my parent module.

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Below is my implementation of creating a dynamic menu item. Firstly I create a new action to point the menu item too and then create the new menu item. In the below example this is being made in  a create function when I create a new record in a table. Be sure to delete these actions/menuitems manually if you uninstall and reinstall the module. Hope this helps.

action_vals = {
'name': vals['menu_name'],
'xml_id': 'module_name.documents_list_action',
'res_model': 'business.management',
'type': 'ir.actions.act_window',
'target': 'current',
'view_mode': 'tree,form',
'domain': "[('le_document_type', '=', '" + vals['menu_name'] + "')]",
}
action = self.env['ir.actions.act_window'].create(action_vals)

###get the parent menu item
parent_menu = self.env['ir.ui.menu'].search([('name', '=', 'DropDownParentMenuItem')])
for menu in parent_menu:
if menu.parent_id.name == 'ModuleParentMenuItem':
parent_id = menu.id
parent_path = menu.parent_path
menu_item_vals = {
'action': 'ir.actions.act_window,%d' % (action.id,),
'active': True,
'display_name': vals['menu_name'],
'name': vals['menu_name'],
'parent_id': parent_id,
'parent_path': parent_path,
}
menu_item = self.env['ir.ui.menu'].create(menu_item_vals)


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