Hi,

Let's say you have a model called model1 and you want to open a form view of another model model2 in a new tab when a button is clicked. Here are the steps:

add a button to trigger the action:

<record id="view_my_model_form" model="ir.ui.view">
    <field name="name">my.model.form</field>
    <field name="model">my.model</field>
    <field name="arch" type="xml">
        <form>
            <!-- Your existing fields go here -->
            <footer>
                <button string="Open Other Model" class="oe_highlight" type="object" name="open_other_model"/>
            </footer>
        </form>
    </field>
</record>

python :

Create model 2 Python and xml files 

Hope it helps

Hi,

You can open record in new tab with below code if your problem still not fixed.

class YourClass1(models.Model):

    _name = 'model1'

    def action_open_record_new_tab(self):

        record_id = # define your record id to open record

        model = 'model2'  # Replace with the actual model name

        # Construct the URL to open the record in a new tab

        url = '/web#id=%s&model=%s' % (record_id, model)

        # You Can add context for passing values

​context = {

​ }

        # Redirect to the URL

        return {

            'type': 'ir.actions.act_url',

            'url': url,

            'target': 'new',  # Open in a new tab/window

            'context': context,

        }

In XML define button for method.

Thanks

if partner has already you can use below code:

base_url = self.env['ir.config_parameter'].sudo().get_param('web.base.url') url = f"{base_url}/web#id={partner_Id}&model=res.partner&view_type=form"

return { 'type': 'ir.actions.act_url', 'url': url, 'target': '_blank' }

here is my code in odoo 17 model res.partner. hope it be can help you!

But in this case it will open the second model as a wizard/pop-up ans not in a browser's new tab