I want to identify certain machines so that no matter which user is logged in some rules will apply to them. Is it possible?
Odoo is the world's easiest all-in-one management software.
It includes hundreds of business apps:
- CRM
- e-Commerce
- Accounting
- Inventory
- PoS
- Project
- MRP
This question has been flagged
5
Odgovori
7519
Prikazi
Hi,
You can get the logged in machine details using the following code.
import httpagentparser
agent = request.httprequest.environ.get('HTTP_USER_AGENT')
agent_details = httpagentparser.detect(agent)
user_os = agent_details['os']['name']
browser_name = agent_details['browser']['name']
ip_address = request.httprequest.environ['REMOTE_ADDR']
From the above code you will get the IP address of the logged system, Browser and OS details.
You can also check with this community modules, but it is not in v7.
https://www.odoo.com/apps/modules/10.0/login_user_detail/
https://www.odoo.com/apps/modules/10.0/user_login_alert/
Thanks
How do I get the request object?
above code is return inside the controller. You can check the modules in the given link, that will give you more info
User login alert gives error as "Unable to install module "user_login_alert" because an external dependency is not met: No module named httpagentparser" Please assist.
`pip install httpagentparser` should solve your issue
Enjoying the discussion? Don't just read, join in!
Create an account today to enjoy exclusive features and engage with our awesome community!
Prijavi| Related Posts | Odgovori | Prikazi | Aktivnost | |
|---|---|---|---|---|
|
2
mar. 24
|
11362 | ||
|
2
avg. 21
|
13571 | ||
|
1
dec. 19
|
5410 | ||
|
|
0
sep. 17
|
3587 | ||
|
|
0
avg. 17
|
2909 |
You can extract useful info from httprequest: https://learnopenerp.blogspot.com/2020/07/get-web-httprequest-in-odoo.html