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I'm trying to create a ir.cron and that cron do something depending on a condition, but no success:
Code:
for record in records:
if record.name == '000000156':
record.write({'name': '!00000156'})
Error:
return unsafe_eval(c, globals_dict, locals_dict)
File "", line 1, in <module>
ValueError: <class 'TypeError'>: "'NoneType' object is not iterable" while evaluating
"for record in records:\n if record.name == '000000156':\n record.write({'name': '!00000156'})"
Hi,
Check below for reference for creating a basic ir.cron
<?xml version="1.0" ?>
<odoo>
<data noupdate="1">
<record id="backup_scheduler" model="ir.cron">
<field name="function">schedule_backup</field>
<field name="interval_type">work_days</field>
<field name="name">Backup scheduler</field>
<field name="numbercall">-1</field>
<field name="priority">5</field>
<field name="doall">False</field>
<field name="active">False</field>
<field name="interval_number">1</field>
<field name="model">db.backup</field>
</record>
</data>
</odoo>
Here schedule_backup is the function and db.backup is the model, you can write the functions for manipulation in schedule_backup. For More reference visit Automated action in Odoo
The error above indicates the null data in records
Hope it helps
I know how to create a ir.cron, that's not the question. How can I manipulate records throught ir.cron by using python code, something like:
if recor.name == something: do something else.
That's the question. I know that its possible to do that by using server action, but how it workds by using cron?
Okay I found a way. Looks like that ir.cron works on model level, in order to manipulte records, i need to call a method(model.my_method) on my cron and on that method, do self.search and then manipulate the records on it. Thanks anyway.
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