Added my code in the comment to the accepted answer.  That code got me the answer that the post was asking for.

1.000 >> 1

1.100 >> 1.1

1.110 >> 1.11

1.111 >>> 1.111

Hi,

Please try this

<span t-esc="'%.0f'% line.qty"/>

Thanks !!!  

Aswini @ iWesabe

You could use Python to convert a `float` into a `str` and then strip it of the trailing zeros. For example:

>>> for x in (1, 2.000, 2.750): str(x)
... 
'1'
'2.0'
'2.75'

So we can define a function like this:

def parse_num(x):
    x = str(x)
    integer, decimals = x.split('.') if '.' in x else (x, None)    
    if decimals in ('0', None):
        return integer
    else:
        return x

Which results in:

>>> for x in (1, 2.000, 2.750): parse_num(x)
... 
'1'
'2'
'2.75'

So maybe you could try with this:

<t t-set="mod_qty">
    formatLang(l.quantity, digit=0)
</t>
<t t-if="mod_qty == l.quantity">
    <span><t t-esc="parse_num(mod_qty)"/></span>
</t>
<t t-if="mod_qty != l.quantity">
    <span><t t-esc="parse_num(l.quantity * 1)"/></span>
</t>

Try this:

<t t-if="mod_qty == l.quantity">
<span><t t-esc="int(float(mod_qty))"/></span>
</t>
<t t-if="mod_qty != l.quantity">
<span><t t-esc="int(float(l.quantity * 1))"/></span>
</t>