How to check for and delete a many2one field record in Studio using Execute Code Action.

Question

I am trying to make an automation using studio's automations, I am doing it with the execute code action, what I want it to do is see if a many2one field exists, if it does delete that record. How do I do it only in studio (v18)? See this code snippet:
# Check if the record has a partner_id
if record.partner_id:
client = record.partner_id
# Attempt to find a lead linked to the client
# Need to verify if the lead exists and delete it
# Unsure how to proceed with checking and deletion in Studio

Dario Bösch · Answer

You can get the opportunities from the field client.opportunity_ids. If you want to get all leads, you need to search for them:

# Check if the record has a partner_id
if record.partner_id:
client = record.partner_id
# Attempt to find a lead linked to the client
lead_ids = record.env['crm.lead'].search([('partner_id', '=', client.id)])
# Check if any leads found
if lead_ids:
lead_ids.unlink() Note that the check /if lead ids were found/ is not necessary and you can directly call unlink on the re

Powiązane posty	Odpowiedzi	Widoki
Execute code complete field with input date + X days studio automation execute code	1 sty 25	1149
Odoo 10 - Counting values of linked records python code models studio odoo10.0	0 lut 17	3630
Display Debit and Credit in USD in Journal Items python studio	1 lut 25	1300
Studio Automations ? for the non-programmer studio automation	4 maj 24	2846
How to send parent record value to child record(s) using Python code and the improved Automations? python automation	0 lis 23	1634

To pytanie dostało ostrzeżenie

Podoba Ci się ta dyskusja? Dołącz do niej!