Skip ke Konten
Pertanyaan ini telah diberikan tanda
xmlxmlrpcrpcodooV8
3 Replies
42008 Tampilan
Avatar
E.M.

I am learning how to use XML RPC, however I am not even able to pass the basic connectivity test.

Any help is really welcomed:

# python
Python 2.7.3 (default, Jun 22 2015, 19:33:41)
[GCC 4.6.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import xmlrpclib
>>> info = xmlrpclib.ServerProxy('http://localhost:8069').start()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.7/xmlrpclib.py", line 1233, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.7/xmlrpclib.py", line 1587, in __request
    verbose=self.__verbose
  File "/usr/lib/python2.7/xmlrpclib.py", line 1273, in request
    return self.single_request(host, handler, request_body, verbose)
  File "/usr/lib/python2.7/xmlrpclib.py", line 1321, in single_request
    response.msg,
xmlrpclib.ProtocolError: <ProtocolError for localhost:8069/RPC2: 404 NOT FOUND>
>>>


Regarding open ports:

# netstat -ta
Active Internet connections (servers and established)
Proto Recv-Q Send-Q Local Address           Foreign Address         State
tcp        0      0 localhost.localdom:8069 *:*                     LISTEN
tcp        0      0 *:ssh                   *:*                     LISTEN
tcp        0      0 localhost.lo:postgresql *:*                     LISTEN
tcp6       0      0 [::]:https              [::]:*                  LISTEN
tcp6       0      0 [::]:http               [::]:*                  LISTEN

 


Avatar
Buang
Avatar
E.M.
Penulis Jawaban Terbai

Already found the answer by rereading the docs:

# cat testrpc2.py
import xmlrpclib
url = 'http://localhost:8069'
db = 'mydb1'
username = 'admin'
password = 'xxxxxxxx'
common = xmlrpclib.ServerProxy('{}/xmlrpc/2/common'.format(url))
output = common.version()
print output
# python testrpc2.py
{'server_version_info': [8, 0, 0, 'final', 0], 'server_serie': '8.0', 'server_version': '8.0-20150726', 'protocol_version': 1}

Avatar
Buang
Avatar
isias mateo mateo
Jawaban Terbai

Hi, i need for odoo 11 with 

import xmlrpc.client


Avatar
Buang
Avatar
Chetan
Jawaban Terbai

For Odoo 15 and Python version 3.8


import xmlrpc.client
url = "http://localhost:8069"

db = "mydatabase" #database name here

username = 'admin'

password = "admin"

common = xmlrpc.client.ServerProxy('{}/xmlrpc/2/common'.format(url))

ver= common.version()   

print(ver)
uid = common.authenticate(db, username, password, {})

print(uid) # Check access expected to print 2


Avatar
Buang
Post Terkait Replies Tampilan Aktivitas
How to show full size list view in a m2m selection Diselesaikan
xml odooV8
Avatar
Avatar
1
Jan 23
3362
How to creare drill down tree view in odoo V8 ? Diselesaikan
xml odooV8
Avatar
Avatar
3
Agu 20
5919
how i can create automatic in one2many field (gmat.dashboard), thos after change (click) date field (in gmat.board)
xml odooV8
Avatar
0
Feb 18
3529
Error curl call xml-rpc res.users model (search_read)
xmlrpc odooV8
Avatar
0
Mei 16
8173
How to create dynamic workflow?
xml odooV8
Avatar
0
Apr 16
5212