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Using 'len()' in order of search function

Jaysinh Shukla
on 3/11/14, 9:06 AM 869 views

I want to apply the len(one2many_field) in Search method of ORM. Like this search(..,order = "len(one2many_field)",..) .I want to order the result by finding total number of their children. The one2many field is in the relation to the same table. Presently I am not able to use len() in order.

Example :

 id    name    parent_id
  1     A       - 
  2     B       1 
  3     C       1 
  4     D       - 
  5     E       4

Result :


Sudhir Arya (SA)

--Sudhir Arya (SA)--
| 6 8 8
Ahmedabad, India
--Sudhir Arya (SA)--

Working as an OpenERP/Odoo developer and a Team Leader 

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Sudhir Arya (SA)
On 3/11/14, 10:51 AM

In order parameter you can only pass fields name. Search method sorts the ids based on your given field and returns them. You cannot give numbers in order parameter.

In limit=50 you can use numbers.

Okay. Then what are the other ways to arrange then by their length of children. You can see what I want to do in the above example. Thanking you.

Jaysinh Shukla
on 3/12/14, 1:29 AM

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Asked: 3/11/14, 9:06 AM
Seen: 869 times
Last updated: 3/16/15, 8:10 AM