Odoo Help


6 Answers
Eric United States
12/31/13, 4:21 PM

Well I finally got something working. This is what I did, I used the database cursor and wrote an sql select statement like this:

cr.execute('select "id" from "table_name" order by "id" desc limit 1')

id_returned = cr.fetchone()

the fetchone() method returns a tuple of one value which is assigned to the id_returned variable. I can then get the id from the tuple by referencing the first index like this: id_returned[0]


Atul Arvind India

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Atul Arvind India
1/1/14, 1:43 AM

If you don't want to execute PSQL query then you can search the record and get the max number, eg.

search_ids = self.pool.get("res.partner").search(cr, uid, [])
last_id = search_ids and max(search_ids)
thompsonn Russian Federation
3/19/17, 4:33 AM

Not quite sure about the older versions but you can do it like this in the newer ones:

last_id = self.env['table.name'].search([])[-1].id
1 Comment
Andreas Stange Panama
8/7/18, 2:52 PM

The ordering of the table might be such that the highest id is not equivalent to the last entry in the list. Thus I would explicitly provide the order in the search method:

last_id = self.env['table.name'].search([], order='id desc')[0].id

Rich Granata United States
1/2/14, 2:30 PM

The sequencing is also stored in the database and can be retrieved with a statement like:

select * from res_partner_id_seq

Olivier DUCROT France
11/10/17, 5:14 AM

you can use something like this :


the solution like the above does not work. It returns the id of the last one in the search() method, but the ids are not sorted. The last id should not be the max one.

last_id = self.env['table.name'].search([])[-1].id
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