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Define tree view sorting directly in the XML definition?

By
Mariano Ruiz
on 12/10/13, 11:04 AM 1,455 views

I know we can define in the object with "_order", but I have a one2many field, with stock moves references, and I do not want to redefine the stock moves sort in all views, just in this tree view.

Also is ridiculous put a functional field in the model, or define a new in memory object model just for this, there must be some practical way to do this from the view definition.

I have the same problem.

Yug Faa
on 2/11/14, 6:55 AM

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Asked: 12/10/13, 11:04 AM
Seen: 1455 times
Last updated: 3/16/15, 8:10 AM