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my time format is '%Y-%m-%d %H:%M:%S'
start_time = 2014-12-04 08:10:32
end_time = 2014-12-04 12:34:45
Here i want output like diff_time = 4.24
Thanks in advance...
from datetime import datetime
fmt = '%Y-%m-%d %H:%M:%S'
d1 = datetime.strptime('2014-12-04 08:10:32',fmt) #start date
d2=datetime.strptime('2014-12-04 12:34:45',fmt) #end date
diff=d2-d1 #calculate difference between start-end date
final output=total seconds/3600.0 #convert total seconds into hours Difference in float format
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|Asked: 12/4/14, 4:39 AM|
|Seen: 5837 times|
|Last updated: 3/16/15, 8:10 AM|