Skip to Content
Menu
This question has been flagged
2 Replies
1500 Views

I would like to use an existing view in another menu by adding some new fields. When i execute that, it is the same view which is show. it doesn't take my new fields. someone can help ?

Avatar
Discard

Can you please show whatever you tried.

Author

Here is my code :

<record id="lbudget_id" model="ir.ui.view">

<fieldname="name">Ligne budgetaire</field>

<field name="model">budg_lbudget</field>

<field name ="priority" eval ="16"/>

<field name ="arch" type ="xml">

<-- Fields for the first view-->

</field>

</record>

<record id="validerbudget_id" model="ir.ui.view">

<field="name">Valider budget</field>

<field name="model">budg_lbuget</field>

<field name ="priority" eval ="16"/>

<field name ="arch" type ="xml">

<-- Fields for the first view-->

<-- Fields that i want to add in the second view-->

</field>

</record>

<record id="budget_id" model="ir.actions.act_windows" id="act_budget">

<field="name">Budget</field>

<field="res_model">budg_lbudget</field>

<field="view_model">tree,form</field>

</record>

<record id="validebudget_id" model="ir.actions.act_windows" id="act_validebudget">

<field="name">Valider budget</field>

<field="res_model">budg_lbudget</field>

<field="view_model">tree,form</field>

<field="view_id" ref="lbudget_id"/>

</record>

How to display two or more form and tree view for same model. You can define different tree and form view for same model. To achieve this we will create a split action for our object/model.

Reference: https://goo.gl/8ypbbg

Best Answer

Hi,

You need to create a new view which inherit from initial wiew like this:


<record id="recor_id" model="ir.ui.view">
<fieldname="name">yourname</field>
<field name="model">model.name</field>
<field name="inherit_id" ref="moduleName.idParentWiew"/>
<field name="arch" type="xml">
<-- Fields you want add-->
</field>
</record>



Avatar
Discard