I made a custom web controller and I want to link to the action of that controller inside a view form to download a file. The only problem I am facing currently is to show the link in the view for the user to click, at this point I don't care if it looks like a button or a link anything or any help would be appreciated. Bellow is the code for the controller and the form inside of which I want the link/button to appear.

#controller class MyController(http.Controller): _cp_path = '/sc'

@http.httprequest
def some_html(self, req, s_action=None, **kw):
    return req.make_response(open('/home/ramywafa/openerpworkspace/imms_modules/imms_crew/controllers/templates/1.docx').read(),
           [('Content-Type', 'application/octet-stream; charset=binary'),
           ('Content-Disposition', content_disposition('1.docx', req))],
        )

#xml view <record model="ir.ui.view" id="view_sefarer_applicant_form"> .... <sheet>