How to display all dates between two dates ?

Question

When two dates are given for eg: start date-: 05/01/2016 end date : 05/03/2016 ..from january to march ..i want to display all the dates between these two dates.

Anil Kesariya · Accepted Answer

Undan,
Here you Go!
import datetime
t_date = datetime.datetime.today()
num_of_day = 10 # This is different between two date range, you just find difference and use as numb_of_day
date_list = [base - datetime.timedelta(days=x) for x in range(0,  num_of_day)]
print "Day List in Datetime Format:", date_list
This might help you,
Regards,
Anil.

iWesabe Technologies · Answer

def dates_between_str_dates(self, date1, date2, mode='date'):
date_from = fields.Date.from_string(date1)
date_to = fields.Date.from_string(date2)
delta = date_to - date_from
if delta.days < 0:
return None
res = []
for n in range(delta.days + 1):
if mode == 'date':
res.append(date_from + timedelta(days=n))
if mode == 'string':
res.append(fields.Date.to_string(date_from + timedelta(days=n)))
return res   Add this function. Parameter * mode * is to specify output type * string */* date *.
Thanks !

Deepak · Answer

fmt = '%Y-%m-%d'
d1 = datetime.strptime(from_date , fmt)
d2 = datetime.strptime(to_date , fmt)
dates_btwn = d1
while dates_btwn <= d2:
print  "dates_between=========>>>" , dates_btwn.date()
dates_btwn = dates_btwn + relativedelta.relativedelta( days = 1 )
This will display the dates between two dates..Hope this will help You..

Tarek Mohamed Ibrahim · Answer

use the following function, it is based on using the 'timedelta'

*from datetime import datetime, timedelta*
* #show dates between two dates
*
*def get_date_list(date1, date2):*
*    date_list = []*
*    loop_dt = date1*
*    print loop_dt*
*    while loop_dt < date2:*
*        loop_dt = loop_dt + timedelta(days=1)*
*        print loop_dt*
*
*
*get_date_list( datetime(2016,1,5), datetime(2016,03,5))*

you can change it to return a list of dates

Hetashree Chauhan (hch) · Answer

import datetime
today = datetime.datetime.today()
numdays = 10
date_list = [today - datetime.timedelta(days=x) for x in range(0, numdays)]
print 'date_list',date_list

Neha Patel (nat) · Answer

from datetime import date, timedelta as td
dt1 = date(2016, 7, 10)
dt2 = date(2016, 7, 19)
delta = dt2 - dt1
for i in range(delta.days + 1):
print dt1 + td(days=i)

i hope it might help you

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